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This article will explain in detail the number of bytes needed to store 1024 24 × 24 dot matrix Chinese character font codes in the computer. The editor thinks it is very practical, so I will share it for you as a reference. I hope you can get something after reading this article.

A dot matrix is a bit (bit), and a 24-bit dot matrix is 24 * 24 bits (bit). If a byte equals 8 bits (bit), then 24 bits 24 dot matrix is 72 bytes, that is, 24 bits 24 bits 8 bits 72. Then 1024 24-inch 24-dot matrices would require 1024-72-73728 bytes.

The operating environment of this tutorial: windows7 system, Dell G3 computer.

A dot matrix is a bit (bit), and a 24-bit dot matrix is 24 * 24 bits (bit). If a byte equals 8 bits (bit), then 24 bits 24 dot matrix is 72 bytes, that is, 24 bits 24 bits 8 bits 72. Then 1024 24-inch 24-dot matrices would require 1024-72-73728 bytes.

The above picture is a 16-16 lattice, which can be seen from the picture that the lattice is a plane. Therefore, there are 256 points in 16-16 and 576 points in 24-24. So when we do the calculation, it's 24, 24, 24, 8 instead of 24.

Extended data

Dot matrix font divides each character into N × N or M × M dots, and then uses the virtual and real of each point (which can be represented by 0 or 1) to represent the outline of the character. Dot matrix fonts are also called bitmap fonts, in which each glyph is represented by a set of two-dimensional pixel information. In computer and telecommunications technology, a character is the basic information of a glyph, glyph-like unit or symbol of a unit.

This is the end of the article on "how many bytes are needed to store 1024 24 × 24 Chinese character font codes in the computer". I hope the above content can be of some help to you, so that you can learn more knowledge. if you think the article is good, please share it for more people to see.

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