Shulou(Shulou.com)05/31 Report--

This article introduces the knowledge of "what are the methods of C++ string inversion". In the operation of actual cases, many people will encounter such a dilemma, so let the editor lead you to learn how to deal with these situations. I hope you can read it carefully and be able to achieve something!

/ * Analysis process: assume that the passed string is a constant const string, so that the operation is more flexible, and the literal value of the string can be passed directly for reversal. The common solution is to define a new character array equal to the length of the passed string, then copy the string and place the str characters into the character array from left to right. Then use a loop to reverse * / / * characters in the character array. First, using the above solution, pass to the const type C-style character pointer, return to the char* type * / / directly use the character array assignment char* strrev1 (const char* str) {const size_t length = strlen (str) / / find the character length char * temp = new char [length]; / / create a new character array of equal length strcpy (temp,str); / / copy for (size_t I = 0; I tmp) {char t = * tmp; * tmp++ = * p; * Plam-= t;} return ret } / / is basically similar to the previous function, except that this function uses shift operations to change the character pointer to char* strrev3 (const char* str) {char* tmp = new char [strlen (str) + 1]; strcpy (tmp,str); char* ret = tmp; char* p = tmp + strlen (str)-1; while (p > tmp) {* p ^ = * tmp * tmp++ ^ = * p; * pmurf-^ = * tmp;} return ret;} / / Save a few steps and directly assign an inverted value to the newly created character array. Hehe, it is simple and clear, but the loop executes char* strrev4 (const char* str) {char* temp = new Charlen (str) several times; for (int I = 0; I c_str (); cout

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