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This article shows you how to achieve multi-table correlation statistics in mysql, concise and easy to understand, absolutely can make you shine, through the detailed introduction of this article I hope you can gain something.

Requirements:

Statistics of reward amount for each book, recharge data statistics at different times, consumption statistics,

Design four tables, book table, orders table reward_log reward table consume_log consumption table, associate with book table through book_id,

Question:

When there are more than two tables associated, the data is duplicated in statistics. We have to use subquery to find out. Subquery can only search one field. Here, CONCAT_WS function is used to concatenate multiple fields.

Achieve:

The query code is as follows

SELECTb.id,b.book_name,sum( IF ( o.create_time > 0 && o.create_time

< 9999999999, o.price, 0 ) ) today_pay_money,sum( IF ( o.create_time >

0 && o.create_time

< 9999999999, 1, 0 ) ) today_pay_num,sum( IF ( o.create_time >

999 && o.create_time

< 9999, o.price, 0 ) ) yesterday_pay_money,sum( IF ( o.create_time >

999 && o.create_time

< 9999, 1, 0 ) ) yesterday_pay_num,sum(o.price) total_pay_money,sum( IF ( o.create_time >

9999 && o.create_time

< 99999, 1, 0 ) ) total_pay_num,( SELECT SUM( total_score ) FROM book_reward_log WHERE book_id = b.id ) total_score,( SELECT CONCAT_WS( ',', SUM( IF ( create_time >

0 && create_time

< 998, score, 0 ) ), SUM( IF ( create_time >

9999 && create_time

< 99998, score, 0 ) ), SUM( IF ( create_time >

99999 && create_time

< 999998, score, 0 ) ) ) FROM book_consume_log WHERE book_id = b.id ) score FROM book_book b LEFT JOIN book_orders o ON b.id = o.bidGROUP BY b.id 查询结果

score is three consumption numbers separated by commas

performance analysis

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