How to use leetcode to realize Z-shape Transformation in golang
How to use leetcode to realize glyph transformation in golang? in view of this problem, this article introduces the corresponding analysis and solution in detail, hoping to help more partners who want to solve this problem to find a more simple and feasible method.
Z-arranges a given string from top to bottom and left to right based on a given number of lines.
For example, if the input string is "LEETCODEISHIRING" and the number of lines is 3, the arrangement is as follows:
L C I R
E T O E S I I G
E D H N
After that, your output needs to be read line by line from left to right to produce a new string, such as "LCIRETOESIIGEDHN".
Please implement this function that converts a string to a specified number of lines:
String convert (string s, int numRows)
Example 1:
Enter: s = "LEETCODEISHIRING", numRows = 3
Output: "LCIRETOESIIGEDHN"
Example 2:
Enter: s = "LEETCODEISHIRING", numRows = 4
Output: "LDREOEIIECIHNTSG"
Explanation:
L D R
E O E I I
E C I H N
T S G
Ideas for solving the problem:
1, for letters, graphics, we can not find the rules intuitively, we use index to represent the graphics, it is easy to find the rules
2, for example 1 is available
0 4 8
1 3 5 7 9
2 6 10
For example 2, available
0 6 121 5 7 11 132 4 8 10 143 9 15
3, we can get the following rule (assuming the index of the letter in the string is I)
A, for each complete column (the column containing the number of numRows), the row index of the data is I% (2*numRows-2)
B, for incomplete column data, we first save it to a map that temporarily contains 2*numRows-2 column data, as follows:
0 4 8
1 5 9
2 6 10
3 7 / / I% (2*numRows-2) > = numRows
C, convert the above temporary map into the final map. For the data of I% (2*numRows-2) > = numRows, move to the next column, the numRows-2-j%numRows position of the next column, and the transformation is completed.
Detailed code
Func convert (s string, numRows int) string {if numRows
