How to write the code of calculator in C language
This article mainly introduces the relevant knowledge of how to write the code of the calculator in C language, the content is detailed and easy to understand, the operation is simple and fast, and it has a certain reference value. I believe that after reading this C language calculator code how to write the article will have a harvest, let's take a look.
Two methods of C language Calculator
/ / General practice # include#include//#includevoid menu () {printf ("* *\ n"); printf ("* Welcome to the calculator page *\ n"); printf ("* 1.add 2.mul *\ n") Printf ("* 3.sub 4.div1 *\ n"); printf ("* 0.exit *\ n"); printf ("* *\ n");} int add (int x, int y) {return x + y;} int mul (int x, int y) {return x * y } int sub (int x, int y) {return x-y;} int div1 (int x, int y) {return x / y;} int main () {int n = 1; menu (); while (n) {printf ("Please enter options:\ n"); scanf ("% d", & n); int x = 0, y = 0 / * printf ("Please enter two integers!\ n"); scanf ("% d% d", & x, & y) * / / if you put two numeric inputs here, you cannot exit the system when an error occurs. Instead, the prompt "enter two integers" switch (n) {case 1: printf ("Please enter two integers!\ n"); scanf ("% d% d", & x, & y) Printf ("% d\ n", add (x, y)); break; case 2: printf ("Please enter two integers!\ n"); scanf ("% d% d", & x, & y); printf ("% d\ n", mul (x, y)); break Case 3: printf ("Please enter two integers!\ n"); scanf ("% d% d", & x, & y); printf ("% d\ n", sub (x, y)); break; case 4: printf ("Please enter two integers!\ n") Scanf ("% d% d", & x, & y); printf ("% d\ n", div1 (x, y)); break; case 0: printf ("exit Calculator! \ n "); break; default: printf (" input error, please enter again!\ n ");}
/ / use function pointer array to solve calculator problems # include#include//#includevoid menu () {printf ("* *\ n"); printf ("* Welcome to the calculator page *\ n"); printf ("* 1.add 2.mul *\ n") Printf ("* 3.sub 4.div1 *\ n"); printf ("* 0.exit *\ n"); printf ("* *\ n");} int add (int x, int y) {return x + y;} int mul (int x, int y) {return x * y } int sub (int x, int y) {return x-y;} int div1 (int x, int y) {return x / y;} int main () {int n = 1; menu (); while (n) {printf ("Please enter options:\ n"); scanf ("% d", & n); int (* arr [5]) () = {0m addmento subhead div1} / / transfer table / / define an array of function pointers that hold the function address if (n > = 0 & & n)
< 5) { int x = 0, y = 0; printf("请输入两个整数:>\ n "); scanf ("% d% d ", & x, & y); printf ("% d\ n ", (* arr [n]) (xPowery)); / / output result} else {printf (" input error, please re-enter!\ n "); scanf ("% d ", & n) }} system ("pause"); return 0;}
Compared with the two methods, the first kind of code is more similar, more redundant; the second kind of code is simple and intuitive, and the program efficiency is high.
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