Shulou(Shulou.com)06/02 Report--

In this issue, the editor will bring you about how to find the intersection of two strings in c language. The article is rich in content and analyzes and narrates it from a professional point of view. I hope you can get something after reading this article.

Finding the intersection of two strings seems simple, but there are a lot of details to consider.

My train of thought:

1. Simplify the two strings and reduce the repeated letters to one.

two。 Concatenate two strings and find out the characters that repeat twice with the help of a loop.

When you have an idea, start writing code.

1. Main () function

Train of thought:

1. Define two arrays tt [M], pp [M] that store strings

two。 Define the pointer * p to receive the return value of fun2 () and output intersection

3. Enter two strings (note the out-of-bounds problem here)

4. Call function

5. Output intersection

# include # include / / use strcat (), strlen () function # define M 50 void fun1 (char tt []); / / remove the same letters from the string char * fun2 (char tt []); / / find the duplicate (subset) int main () {char tt [M], pp [M]; / / define two arrays to store the string char * p / / accept the address returned by fun2 () and output the intersection string int i; gets (tt); / / abcdef123abc12 gets (pp); / / acef123ace124 fun1 (tt); / / call the function fun1 (pp) / / printf ("% s\ n", tt); / / for inspection use / / printf ("% s\ n", pp); strcat (tt,pp); / / printf ("% s\ n", tt); p=fun2 (tt); / / call function for (iDeplox * (pamphi)! ='\ 0' ) {printf ("% c", * (pairi)); / / acef123} return 0;} II. Fun1 () function

The function of fun1 () is to keep only one repeated character in the string.

Train of thought:

1. First of all, replace the repeated characters with''(here is a space).

two。 Remove''(space) after moving string array elements

Void fun1 (char tt []) / / erase the repetitive characters {int iJournal j; char ch; for

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