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Python in how to randomly disrupt the list sorting, many novices are not very clear about this, in order to help you solve this problem, the following editor will explain for you in detail, people with this need can come to learn, I hope you can gain something.

Scene:

Now there is a list: [1, 2, 3, 3, 4, 5, 6], I need to output this list in a random scrambled form.

Professional point terminology: traverse the data in a container one by one at a time.

Note: do not generate a random list set.

Environment:

Python 3.6

Solution: solution 1:

Someone may use Random built-in functions to indirectly achieve the desired results. But this way is too primitive, not elegant enough, and there is a suspicion of repeating the wheel. Here I will not post the effects I have achieved through random.

Option 2:

There is a random.shuffle () method in Random that provides the perfect solution. The code is as follows:

X = [1, random.shuffle, 2, 3, 4, 5, 6] print (x)

Output result:

First output: [6, 5, 1, 3, 2, 4] second output: [6, 1, 3, 5, 2, 4] third output: [5, 3, 1, 2, 4, 6]

As we can see from the results, the output is completely random, with only two lines of code, no random, no for loop.

Source code interpretation:

This part of the original link: how to use random.shuffle () to disrupt the order of lists in Python [1]

Def shuffle (self, x, random=None): "Shuffle list x in place, and return None. Scramble the list in place and do not generate a new list.

Optional argument random is a 0-argument function returning a random float in [0.0,1.0); if it is the default None, the standard random.random will be used. The optional parameter random is a function from 0 to argument that returns a random floating point in [0.0recoery 1.0); if random is the default value None, the standard random.random () is used. "

If random is None: randbelow = self._randbelow for i in reversed (range (1, len (x): # pick an element in x [: iTh1] with which to exchange x [I] j = randbelow (iTh1) x [I], x [j] = x [j], x [I] else: _ int = int for i in reversed (range (1) Len (x)): # pick an element in x [: iTun1] with which to exchange x [I] j = _ int (random () * (iTun1)) x [I], x [j] = x [j], x [I]

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