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The content of this article mainly focuses on how to analyze the time operation and time difference calculation method of Shell. The content of the article is clear and clear. It is very suitable for beginners to learn and is worth reading. Interested friends can follow the editor to read together. I hope you can get something through this article!

Recently, when dealing with Shell scripts, I encountered a problem of processing time. The addition and subtraction of time, and the calculation of time difference.

one. Time addition and subtraction

The way to deal with it here is to convert the basic time into a timestamp, and then you need to add or change the time to seconds.

For example, 1990-01-01 01:01:01 plus 1 hour and 20 minutes

Treatment method:

a. Convert the base time to a timestamp

Time1=$ (date +% s-d '1990-01-01 01purl 01purl 01')

Echo $time1

631126861 [timestamp]

b. Turn the increased time into seconds

[root localhost ~] # time2=$ ((1 / 60 / 60 / 20 / 60))

[root localhost ~] # echo $time2

4800

c. The two times are added together to calculate the result time.

Time1=$ (($time1+$time2))

Time1=$ (date +% Y-%m-%d\% H:%M:%S-d "1970-01-01 UTC $time1 seconds")

Echo $time1

1990-01-01 02:21:01

two. Time difference calculation method

For example, the 11:11:11 time difference between 2010-01-01 and 2009-01-01

Principle: also convert to timestamp, and then calculate days, hours, minutes, seconds

Time1=$ (($(date +% s-d '2010-01-01')-$(date +% s-d '2009-01-01 11))

Echo time1

Change time1 / 60 seconds into minutes.

Supplementary note:

Shell single parenthesis operation symbol:

Axiom $(date)

Equivalent to: a=date

Double parenthesis operator:

Axiom $((1x 2))

Echo $a

Equivalent to:

A=expr 1 + 2

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